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Subprocess.Popen() : hide the cmd shell

I am trying to call an executable at startup, which will call another executable itself. For the first part, I simply added the path to the executable to HKEY_LOCAL_MACHINESOFTWAREMicrosoftWindowsCurrentVersionRun, which works, my executable is called at startup.

The latter contains, among others, these lines :

startupinfo = subprocess.STARTUPINFO()
startupinfo.dwFlags |= subprocess.STARTF_USESHOWWINDOW
startupinfo.wShowWindow = subprocess.SW_HIDE
proc = subprocess.Popen(command, startupinfo=startupinfo)

However, a command shell (cmd) pops when the computer starts. Everything works fine, but it is visible instead of hidden... So basically, how do I hide this command shell ?

When using ProcessExplorer, I have the following hierarchy :

+ System
|_ Interrupts
|_ smss.exe
|_ some processes...
+ explorer.exe
|_ some processes...
|_ MYSCRIPT.EXE

Here is the sequence I try to achieve :

I create an ISO file containing all the Python executable I want to run on the VM. One of them (master.exe) calls the others.
I create a VM which automatically mount the latter
The VM, which was prepared, has a scheduled task which calls D:master.exe
master.exe (among other tasks which are not our concern here) adds the value D:myscript.exe to HKEY_LOCAL_MACHINESOFTWAREMicrosoftWindowsCurrentVersionRun
The VM reboots
D:myscript.exe is run (and it works fine and as attended), but it does run in a command prompt, which I would like to be invisible.

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